The oxidation state and covalency of Al in [A | vedclass

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(D) In the complex $[AlCl(H_2O)_5]^{2+}$,let the oxidation state of $Al$ be $x$.The oxidation state of $Cl$ is $-1$ and $H_2O$ is $0$.So,$x + (-1) + 5

Vedclass · Accepted Answer

$+3$ & $6$

Vedclass · Answer

(D) In the complex $[AlCl(H_2O)_5]^{2+}$,let the oxidation state of $Al$ be $x$.The oxidation state of $Cl$ is $-1$ and $H_2O$ is $0$.So,$x + (-1) + 5(0) = +2$.$x - 1 = +2$,which gives $x = +3$.Thus,the oxidation state of $Al$ is $+3$.The covalency (coordination number) is the total number of coordinate bonds formed by the central metal atom with the ligands.Here,$1$ $Cl^-$ ion and $5$ $H_2O$ molecules are attached to $Al$,so the coordination number is $1 + 5 = 6$.

The oxidation state and covalency of $Al$ in $[AlCl(H_2O)_5]^{2+}$ are $...$ and $...$ respectively.

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