The oxidation number of chromium in sodium te | vedclass

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(B) The chemical formula for sodium tetrafluoro oxochromate is $Na_2[CrF_4O]$.Let the oxidation number of chromium be $x$.The oxidation state of sodiu

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$IV$

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(B) The chemical formula for sodium tetrafluoro oxochromate is $Na_2[CrF_4O]$.Let the oxidation number of chromium be $x$.The oxidation state of sodium $(Na)$ is $+1$,fluorine $(F)$ is $-1$,and oxygen $(O)$ is $-2$.Setting the sum of oxidation states to zero: $2(+1) + x + 4(-1) + (-2) = 0$.$2 + x - 4 - 2 = 0$.$x - 4 = 0$.$x = +4$.

The oxidation number of chromium in sodium tetrafluoro oxochromate complex is

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