The oxidation number of Pt in [Pt(C_2H_4)Cl_3 | vedclass

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(B) Let the oxidation number of $Pt$ be $x$.In the complex ion $[Pt(C_2H_4)Cl_3]^-$,the ligand $C_2H_4$ (ethylene) is a neutral ligand with an oxidati

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$+2$

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(B) Let the oxidation number of $Pt$ be $x$.In the complex ion $[Pt(C_2H_4)Cl_3]^-$,the ligand $C_2H_4$ (ethylene) is a neutral ligand with an oxidation state of $0$.The chloride ion $Cl^-$ has an oxidation state of $-1$.The overall charge on the complex is $-1$.Setting up the equation: $x + 0 + 3(-1) = -1$.$x - 3 = -1$.$x = +2$.Therefore,the oxidation number of $Pt$ is $+2$.

The oxidation number of $Pt$ in $[Pt(C_2H_4)Cl_3]^-$ is

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