(A) Let the oxidation number of $Mn$ be $x$.In $KMnO_4$,the oxidation number of $K$ is $+1$ and the oxidation number of $O$ is $-2$.The sum of oxidati

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(A) Let the oxidation number of $Mn$ be $x$.In $KMnO_4$,the oxidation number of $K$ is $+1$ and the oxidation number of $O$ is $-2$.The sum of oxidation numbers in a neutral molecule is $0$.Therefore,$(+1) + x + 4 \times (-2) = 0$.$1 + x - 8 = 0$.$x - 7 = 0$.$x = +7$.