The output of the circuit is low (zero) for: | vedclass

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(C) The given circuit consists of an $OR$ gate followed by a $NOR$ gate. Let the output of the $OR$ gate be $Z = X + Y$. This $Z$ is fed into both inp

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$(B), (C)$ and $(D)$ only

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(C) The given circuit consists of an $OR$ gate followed by a $NOR$ gate. Let the output of the $OR$ gate be $Z = X + Y$. This $Z$ is fed into both inputs of the $NOR$ gate. The output of the $NOR$ gate is $Out = \overline{Z + Z} = \overline{Z}$.Substituting $Z = X + Y$,we get $Out = \overline{X + Y}$. This is the Boolean expression for a $NOR$ gate.The truth table for the circuit is:$X$$Y$$X+Y$$Out = \overline{X+Y}$$0$$0$$0$$1$$0$$1$$1$$0$$1$$0$$1$$0$$1$$1$$1$$0$From the table,the output is low (zero) for cases $(B)$,$(C)$,and $(D)$.

The output of the circuit is low (zero) for: $(A) \ X = 0, Y = 0$,$(B) \ X = 0, Y = 1$,$(C) \ X = 1, Y = 0$,$(D) \ X = 1, Y = 1$. Choose the correct answer from the options given below:

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