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(A) The given circuit consists of an $OR$ gate and an $AND$ gate.$1$. The inputs to the $OR$ gate are $A$ and $B$. Therefore,the output of the $OR$ ga

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$A$

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(A) The given circuit consists of an $OR$ gate and an $AND$ gate.$1$. The inputs to the $OR$ gate are $A$ and $B$. Therefore,the output of the $OR$ gate is $(A + B)$.$2$. The inputs to the $AND$ gate are $A$ and the output of the $OR$ gate,which is $(A + B)$.$3$. The output $Y$ of the $AND$ gate is the product of its inputs: $Y = A \cdot (A + B)$.$4$. Using the Boolean algebra law of absorption,$A \cdot (A + B) = A$.$5$. Therefore,the final output is $Y = A$.

The output $Y$ of the combination of gates shown is equal to :-

Similar Questions

The truth table given below is for which gate?
$A: 0, 0, 1, 1$
$B: 0, 1, 0, 1$
$C: 1, 1, 1, 0$

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