The outer dimensions of a closed box are 12 t | vedclass

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(B) Since the wood is $1 	ext{ cm}$ thick,the inner dimensions are calculated by subtracting twice the thickness from each outer dimension (because t

Vedclass · Accepted Answer

$480$

Vedclass · Answer

(B) Since the wood is $1 	ext{ cm}$ thick,the inner dimensions are calculated by subtracting twice the thickness from each outer dimension (because the wood is on both sides).Inner length $(l)$ $= 12 	ext{ cm} - 2 	imes 1 	ext{ cm} = 10 	ext{ cm}$.Inner breadth $(b)$ $= 10 	ext{ cm} - 2 	imes 1 	ext{ cm} = 8 	ext{ cm}$.Inner height $(h)$ $= 8 	ext{ cm} - 2 	imes 1 	ext{ cm} = 6 	ext{ cm}$.Capacity of the box $= l 	imes b 	imes h$.Capacity $= 10 	ext{ cm} 	imes 8 	ext{ cm} 	imes 6 	ext{ cm} = 480 	ext{ cm}^3$.

The outer dimensions of a closed box are $12 \text{ cm}$ by $10 \text{ cm}$ by $8 \text{ cm}$. If the box is made of wood $1 \text{ cm}$ thick,find out the capacity of the box (in $\text{cm}^3$).

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