The order of stability of carbonium ions is:
- A$Methyl > Ethyl > Iso-propyl > Tert-butyl$
- B$Tert-butyl > Iso-propyl > Ethyl > Methyl$
- C$Iso-propyl > Tert-butyl > Ethyl > Methyl$
- D$Tert-butyl > Ethyl > Iso-propyl > Methyl$
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Similar Questions
The correct order of the relative stability of the following carbanions is:
$I$. $HC \equiv C^{-}$
$II$. $CH_2=CH-CH_2^{-}$
$III$. $H_2C=CH^{-}$
$IV$. $(C_6H_5)_2CH^{-}$
$I$. $HC \equiv C^{-}$
$II$. $CH_2=CH-CH_2^{-}$
$III$. $H_2C=CH^{-}$
$IV$. $(C_6H_5)_2CH^{-}$
Intermediates formed in the reactions $P$ and $Q$ are:
$P: CH_3-CH=CH_2 \xrightarrow{HCl}$
$Q: CH_3-CH=CH_2 \xrightarrow[\text{Peroxide}]{HCl}$
$P: CH_3-CH=CH_2 \xrightarrow{HCl}$
$Q: CH_3-CH=CH_2 \xrightarrow[\text{Peroxide}]{HCl}$
Difficult
View SolutionAmong the given compounds,choose the two that yield the same carbocation on ionization.
Difficult
View SolutionAmong the given compounds $I, II, III$,the correct order of bond dissociation energy of the $C-H$ bond marked with $*$ is:
DifficultNEET 2025
View SolutionThe most stable carbonium ion is:
Medium
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