The order of increasing ionic radius of the f | vedclass

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(A) To determine the ionic radius,we consider the number of shells and the effective nuclear charge. $1$. $Al^{3+}$ ($10$ electrons,$2$ shells,$Z=13$)

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$Al^{3+} < Mg^{2+} < Li^{+} < K^{+}$

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(A) To determine the ionic radius,we consider the number of shells and the effective nuclear charge. $1$. $Al^{3+}$ ($10$ electrons,$2$ shells,$Z=13$) $2$. $Mg^{2+}$ ($10$ electrons,$2$ shells,$Z=12$) $3$. $Li^{+}$ ($2$ electrons,$1$ shell,$Z=3$) $4$. $K^{+}$ ($18$ electrons,$3$ shells,$Z=19$) Comparing these,$Li^{+}$ has the smallest radius due to having only one shell. Among $Al^{3+}$ and $Mg^{2+}$ (isoelectronic species),$Al^{3+}$ has a higher nuclear charge,so it is smaller. $K^{+}$ has the largest radius as it has $3$ shells. Thus,the increasing order is $Al^{3+} < Mg^{2+} < Li^{+} < K^{+}$.

The order of increasing ionic radius of the following is:

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