The orbital with maximum energy is

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(D) The energy of an orbital is determined by the $(n + l)$ rule,where $n$ is the principal quantum number and $l$ is the azimuthal quantum number.For

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$6d$

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(D) The energy of an orbital is determined by the $(n + l)$ rule,where $n$ is the principal quantum number and $l$ is the azimuthal quantum number.For $3d$: $n=3, l=2$,so $(n+l) = 3+2 = 5$.For $5p$: $n=5, l=1$,so $(n+l) = 5+1 = 6$.For $4s$: $n=4, l=0$,so $(n+l) = 4+0 = 4$.For $6d$: $n=6, l=2$,so $(n+l) = 6+2 = 8$.Since the orbital with the highest $(n+l)$ value has the maximum energy,$6d$ has the maximum energy.

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