The orbital velocity of an artificial satellite in a circular orbit very close to the Earth is $v$. The velocity of a geostationary satellite orbiting in a circular orbit at an altitude of $3R$ from the Earth's surface will be

Write the equation and value of the orbital periodic time of a satellite revolving very close to the surface of the Earth.

Earth revolves around the sun in a circular orbit of radius $R$. The angular momentum of the revolving earth is directly proportional to

$A$ geostationary satellite is orbiting around an arbitrary planet $P$ at a height of $11R$ above the surface of $P$,where $R$ is the radius of $P$. The time period of another satellite in hours at a height of $2R$ from the surface of $P$ is $........$. The planet $P$ has a rotation period of $24\, \text{hours}$.

In a satellite,if the time of revolution is $T$,then the kinetic energy $(K.E.)$ is proportional to:

The orbital angular momentum of a satellite revolving at a distance $r$ from the centre is $L$. If the distance is increased to $16r$,then the new angular momentum will be