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(B) Let the numerator be $x$ and the denominator be $y$. The fraction is $\frac{x}{y}$.According to the first condition,the numerator is $4$ less than

Vedclass · Accepted Answer

$3/7$

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(B) Let the numerator be $x$ and the denominator be $y$. The fraction is $\frac{x}{y}$.According to the first condition,the numerator is $4$ less than the denominator: $x = y - 4$,which implies $y = x + 4$.According to the second condition,if the numerator is decreased by $2$ and the denominator is increased by $1$,the denominator becomes eight times the numerator: $(y + 1) = 8(x - 2)$.Substitute $y = x + 4$ into the second equation: $(x + 4 + 1) = 8(x - 2)$.$x + 5 = 8x - 16$.$5 + 16 = 8x - x$.$21 = 7x$,so $x = 3$.Now,find $y$: $y = x + 4 = 3 + 4 = 7$.The fraction is $\frac{3}{7}$.

The numerator of a fraction is $4$ less than the denominator. If the numerator is decreased by $2$ and the denominator is increased by $1,$ then the denominator becomes eight times the numerator. Find the fraction.

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