The numbers of lone pair(s) on Xe in XeF_2 an | vedclass

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(C) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ covalent bonds with fluorine atoms,leaving $8 - 2 = 6$ electrons,which c

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$3$ and $2$

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(C) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ covalent bonds with fluorine atoms,leaving $8 - 2 = 6$ electrons,which corresponds to $3$ lone pairs.In $XeF_4$,$Xe$ forms $4$ covalent bonds with fluorine atoms,leaving $8 - 4 = 4$ electrons,which corresponds to $2$ lone pairs.Therefore,the number of lone pairs on $Xe$ in $XeF_2$ and $XeF_4$ are $3$ and $2$,respectively.

The numbers of lone pair$(s)$ on $Xe$ in $XeF_2$ and $XeF_4$ are,respectively:

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