The number of ways in which $3$ children can distribute $10$ tickets out of $15$ consecutively numbered tickets among themselves such that they get consecutive blocks of $5, 3$ and $2$ tickets is:

  • A
    $^8C_5$
  • B
    $^8C_5 \times 3!$
  • C
    $^8C_5 \times (3!)^2$
  • D
    none of these

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