The number of water molecules in 250, mL of w | vedclass

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(A) Given: density of water $= 1.0\, g\, mL^{-1}$.Volume of water $= 250\, mL$.Mass of water $= 	ext{density} 	imes 	ext{volume} = 1.0\, g\, mL^{-1

Vedclass · Accepted Answer

$83.6$

Vedclass · Answer

(A) Given: density of water $= 1.0\, g\, mL^{-1}$.Volume of water $= 250\, mL$.Mass of water $= 	ext{density} 	imes 	ext{volume} = 1.0\, g\, mL^{-1} 	imes 250\, mL = 250\, g$.Molar mass of water $(H_2O) = (2 	imes 1) + 16 = 18\, g\, mol^{-1}$.Number of moles of water $= \frac{	ext{Mass}}{	ext{Molar mass}} = \frac{250}{18} \approx 13.889\, mol$.Number of molecules $= 	ext{moles} 	imes 	ext{Avogadro's number} = 13.889 	imes 6.023 	imes 10^{23} \approx 83.65 	imes 10^{23}$.Thus,the number of water molecules is closest to $83.6 	imes 10^{23}$.

The number of water molecules in $250\, mL$ of water is closest to $.....\, \times 10^{23}$.
[Given: density of water is $1.0\, g\, mL^{-1}$; Avogadro's number $= 6.023 \times 10^{23}$]

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The number of water molecules in $250\, mL$ of water is closest to $.....\, \times 10^{23}$.[Given: density of water is $1.0\, g\, mL^{-1}$; Avogadro's number $= 6.023 \times 10^{23}$]