The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled. The reduction factor $K $ will be
The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled. The reduction factor $K $ will be
- A
$K$
- B
$2K$
- C
$4K$
- D
$K/4$
Similar Questions
If the number of turns and radius of cross section of the coil of a tangent galvanometer are doubled, then the reduction factor $K$ will become
If the number of turns and radius of cross section of the coil of a tangent galvanometer are doubled, then the reduction factor $K$ will become
Vibration magnetometer is used for comparing
Vibration magnetometer is used for comparing
The unit of reduction factor of tangent galvanometer is
The unit of reduction factor of tangent galvanometer is
Time period in vibration magnetometer will be infinity at
Time period in vibration magnetometer will be infinity at
A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are mutually perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is $4\, sec$. If one of the magnets is taken away, find the period of oscillation of the other in the same field (in $sec.$) :-
A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are mutually perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is $4\, sec$. If one of the magnets is taken away, find the period of oscillation of the other in the same field (in $sec.$) :-