The number of stereoisomers possible for a co | vedclass

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(A) The given compound is $pent-3-en-2-ol$ $(CH_3-CH=CH-CH(OH)-CH_3)$.This molecule contains one double bond that exhibits geometrical isomerism ($cis

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$4$

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(A) The given compound is $pent-3-en-2-ol$ $(CH_3-CH=CH-CH(OH)-CH_3)$.This molecule contains one double bond that exhibits geometrical isomerism ($cis$ and $trans$) and one chiral center at the $C-2$ position,which exhibits optical isomerism ($R$ and $S$ configurations).For a molecule with $n$ stereocenters (including double bonds capable of geometrical isomerism),the number of stereoisomers is $2^n$ if the molecule is unsymmetrical.Here,$n = 2$ (one double bond + one chiral center).Therefore,the total number of stereoisomers is $2^2 = 4$.These are: $(cis, R)$,$(cis, S)$,$(trans, R)$,and $(trans, S)$.

The number of stereoisomers possible for a compound of the molecular formula $CH_3-CH=CH-CH(OH)-CH_3$ is

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