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(A) The characteristics of physisorption are:$1.$ It is not specific in nature (it is non-specific).$2.$ Enthalpy of adsorption is low $(20-40 \ kJ \

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$2$

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(A) The characteristics of physisorption are:$1.$ It is not specific in nature (it is non-specific).$2.$ Enthalpy of adsorption is low $(20-40 \ kJ \ mol^{-1})$.$3.$ It decreases with an increase in temperature.$4.$ It results in multimolecular layers.$5.$ No appreciable activation energy is needed.Comparing these with the given statements:$A.$ Incorrect (Physisorption is non-specific).$B.$ Incorrect (Enthalpy is low).$C.$ Correct.$D.$ Incorrect (It forms multimolecular layers).$E.$ Correct.Thus,there are $2$ correct statements ($C$ and $E$).

The number of statement/s which are the characteristics of physisorption is
$A.$ It is highly specific in nature
$B.$ Enthalpy of adsorption is high
$C.$ It decreases with increase in temperature
$D.$ It results into unimolecular layer
$E.$ No activation energy is needed

Similar Questions

Adsorption of a gas on a surface follows the Freundlich adsorption isotherm. The plot of $\log \frac{x}{m}$ versus $\log P$ gives a straight line with a slope equal to $0.5$. Then,(where $\frac{x}{m}$ is the mass of the gas adsorbed per gram of adsorbent):

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What are the factors which influence the adsorption of a gas on a solid?

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Reason : Heat keeps on providing more and more activation energy.

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The number of statement/s which are the characteristics of physisorption is$A.$ It is highly specific in nature$B.$ Enthalpy of adsorption is high$C.$ It decreases with increase in temperature$D.$ It results into unimolecular layer$E.$ No activation energy is needed