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(C) To find the number of solutions of the equation $2^x = x^2$,we analyze the intersection points of the functions $f(x) = 2^x$ and $g(x) = x^2$.$1$.

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$3$

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(C) To find the number of solutions of the equation $2^x = x^2$,we analyze the intersection points of the functions $f(x) = 2^x$ and $g(x) = x^2$.$1$. For $x $2$. For $x > 0$: - At $x = 2$,$2^2 = 4$ and $2^2 = 4$. Thus,$x = 2$ is a solution.- At $x = 4$,$2^4 = 16$ and $4^2 = 16$. Thus,$x = 4$ is a solution.- Between $x = 2$ and $x = 4$,the function $x^2$ grows faster than $2^x$ initially,but $2^x$ eventually overtakes $x^2$. Since $2^x$ is convex and $x^2$ is convex,there are no other solutions for $x > 0$ besides $x = 2$ and $x = 4$.Thus,the solutions are $x \approx -0.766$,$x = 2$,and $x = 4$.There are a total of $3$ solutions.

The number of solutions of the equation $2^x = x^2$ is

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