The number of protons,electrons and neutrons | vedclass

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(B) Given: $p = 17$,$e = 18$,$n = 18$. Atomic number $(Z)$ is equal to the number of protons,so $Z = 17$,which corresponds to the element Chlorine $(C

Vedclass · Accepted Answer

$_{17}^{35} Cl^{-}$

Vedclass · Answer

(B) Given: $p = 17$,$e = 18$,$n = 18$. Atomic number $(Z)$ is equal to the number of protons,so $Z = 17$,which corresponds to the element Chlorine $(Cl)$. Since the number of electrons $(18)$ is greater than the number of protons $(17)$,the species carries a negative charge of $-1$,forming the chloride ion $(Cl^{-})$. Mass number $(A)$ is the sum of protons and neutrons: $A = p + n = 17 + 18 = 35$. Therefore,the proper symbol is $_{17}^{35} Cl^{-}$.

The number of protons,electrons and neutrons in a species are equal to $17$,$18$ and $18$ respectively. Which of the following will be the proper symbol of this species?

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