The number of precipitable halide ions in the | vedclass

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Question

(D) The given coordination compound is $[Pt(NH_3)Cl_2Br]Cl$. In an aqueous solution,the complex dissociates as follows: $[Pt(NH_3)Cl_2Br]Cl \rightleft

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(D) The given coordination compound is $[Pt(NH_3)Cl_2Br]Cl$. In an aqueous solution,the complex dissociates as follows: $[Pt(NH_3)Cl_2Br]Cl \rightleftharpoons [Pt(NH_3)Cl_2Br]^+ + Cl^-$. Only the $Cl^-$ ion present outside the coordination sphere is ionizable and can be precipitated by adding silver nitrate $(AgNO_3)$. Therefore,the number of precipitable halide ions is $1$.

The number of precipitable halide ions in the sample $[Pt(NH_3)Cl_2Br]Cl$ will be

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