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(B) The reaction of methylcyclohexane with $Br_2/hv$ involves free radical substitution.Methylcyclohexane has different types of hydrogen atoms availa

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) The reaction of methylcyclohexane with $Br_2/hv$ involves free radical substitution.Methylcyclohexane has different types of hydrogen atoms available for substitution:$1$. The hydrogen on the methyl group (primary carbon).$2$. The hydrogen on the tertiary carbon of the cyclohexane ring (at the position where the methyl group is attached).$3$. The hydrogens on the secondary carbons of the cyclohexane ring at the ortho position.$4$. The hydrogens on the secondary carbons of the cyclohexane ring at the meta position.$5$. The hydrogen on the secondary carbon of the cyclohexane ring at the para position.Thus,there are $5$ distinct positions where bromine can substitute,leading to $5$ structural isomers. Excluding stereoisomers,the total number of monobromo products is $5$.

The number of possible monobromo products for the reaction of methylcyclohexane with $Br_2/hv$ is (excluding stereoisomers):

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