The number of possible isomers of dichloro-ni | vedclass

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(C) To find the number of isomers of dichloro-nitrobenzene $(C_6H_3Cl_2NO_2)$,we consider the relative positions of the two chlorine atoms and the nit

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$6$

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(C) To find the number of isomers of dichloro-nitrobenzene $(C_6H_3Cl_2NO_2)$,we consider the relative positions of the two chlorine atoms and the nitro group on the benzene ring.$1$. If the two chlorine atoms are at the $1,2$-positions (ortho),the nitro group can be at the $3, 4, 5,$ or $6$ positions. However,due to symmetry,the $3$ and $6$ positions are equivalent,and the $4$ and $5$ positions are equivalent. This gives $2$ isomers: $1,2$-dichloro-$3$-nitrobenzene and $1,2$-dichloro-$4$-nitrobenzene.$2$. If the two chlorine atoms are at the $1,3$-positions (meta),the nitro group can be at the $2, 4,$ or $5$ positions. The $2$ position is unique,the $4$ and $6$ positions are equivalent,and the $5$ position is unique. This gives $3$ isomers: $1,3$-dichloro-$2$-nitrobenzene,$1,3$-dichloro-$4$-nitrobenzene,and $1,3$-dichloro-$5$-nitrobenzene.$3$. If the two chlorine atoms are at the $1,4$-positions (para),the nitro group can only be at the $2$ position (which is equivalent to the $3, 5,$ and $6$ positions). This gives $1$ isomer: $1,4$-dichloro-$2$-nitrobenzene.Total number of isomers = $2 + 3 + 1 = 6$.

The number of possible isomers of dichloro-nitrobenzene is

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