The number of oxygen atoms in 0.2 mol of sod | vedclass

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Question

(A) The chemical formula for sodium carbonate decahydrate is $Na_{2}CO_{3} \cdot 10H_{2}O$.Each molecule of $Na_{2}CO_{3} \cdot 10H_{2}O$ contains $3$

Vedclass · Accepted Answer

$1.56 	imes 10^{24}$

Vedclass · Answer

(A) The chemical formula for sodium carbonate decahydrate is $Na_{2}CO_{3} \cdot 10H_{2}O$.Each molecule of $Na_{2}CO_{3} \cdot 10H_{2}O$ contains $3$ oxygen atoms in the carbonate part and $10$ oxygen atoms in the water molecules,totaling $13$ oxygen atoms per formula unit.Therefore,$1 \ mol$ of $Na_{2}CO_{3} \cdot 10H_{2}O$ contains $13 \ mol$ of oxygen atoms.For $0.2 \ mol$ of $Na_{2}CO_{3} \cdot 10H_{2}O$,the number of moles of oxygen atoms is $0.2 	imes 13 = 2.6 \ mol$.The number of oxygen atoms is calculated as $2.6 	imes N_{A} = 2.6 	imes 6.022 	imes 10^{23} \approx 1.5657 	imes 10^{24}$.Rounding to the nearest provided option,the result is $1.56 	imes 10^{24}$.

The number of oxygen atoms in $0.2 \ mol$ of sodium carbonate decahydrate is :-

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