The number of optically active products obtai | vedclass

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(B) The given compound is $CH_3-CH=CH-CH(CH_3)-CH=CH-CH(CH_3)-CH=CH-CH_3$. Upon complete ozonolysis $(O_3/Zn, H_2O)$,the double bonds are cleaved to f

Vedclass · Accepted Answer

$0$

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(B) The given compound is $CH_3-CH=CH-CH(CH_3)-CH=CH-CH(CH_3)-CH=CH-CH_3$. Upon complete ozonolysis $(O_3/Zn, H_2O)$,the double bonds are cleaved to form carbonyl compounds.Specifically,the structure $CH_3-CH=CH-CH(CH_3)-CH=CH-CH(CH_3)-CH=CH-CH_3$ breaks down into:$1$. $CH_3CHO$ (Acetaldehyde) - $2$ molecules.$2$. $OHC-CH(CH_3)-CHO$ (Methylmalonaldehyde) - $2$ molecules.Acetaldehyde $(CH_3CHO)$ is achiral and thus optically inactive.Methylmalonaldehyde $(OHC-CH(CH_3)-CHO)$ has a chiral center at the carbon atom attached to the methyl group. However,in this specific molecule,the two aldehyde groups are identical,making the molecule achiral due to the presence of a plane of symmetry or because it is a meso-like structure in its conformation. Thus,it is optically inactive.Therefore,the number of optically active products is $0$.

The number of optically active products obtained from the complete ozonolysis of the given compound is $:$

Similar Questions

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