The number of neutrons in 5 g of D_2O (D is | vedclass

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(B) The molar mass of $D_2O$ is $(2 	imes 2) + 16 = 20 \ g/mol$.Number of moles of $D_2O = \frac{5 \ g}{20 \ g/mol} = 0.25 \ mol$.In one molecule of

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$2.5$

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(B) The molar mass of $D_2O$ is $(2 	imes 2) + 16 = 20 \ g/mol$.Number of moles of $D_2O = \frac{5 \ g}{20 \ g/mol} = 0.25 \ mol$.In one molecule of $D_2O$ ($D = _1^2H$,$O = _8^{16}O$):Neutrons in $2D = 2 	imes (2 - 1) = 2$.Neutrons in $O = 16 - 8 = 8$.Total neutrons per molecule = $2 + 8 = 10$.Total neutrons in $0.25 \ mol = 0.25 	imes 10 	imes N_A = 2.5 \ N_A$.

The number of neutrons in $5 \ g$ of $D_2O$ ($D$ is $_1^2H$) are ................ $N_A$.

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