The number of moles of sodium sulphite (Na_2S | vedclass

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Question

(B) The balanced chemical equation for the reaction between $Na_2SO_3$ and $KMnO_4$ in an acidic medium is:$5 Na_2SO_3 + 3 H_2SO_4 + 2 KMnO_4 \rightar

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(B) The balanced chemical equation for the reaction between $Na_2SO_3$ and $KMnO_4$ in an acidic medium is:$5 Na_2SO_3 + 3 H_2SO_4 + 2 KMnO_4 ightarrow 5 Na_2SO_4 + 2 MnSO_4 + K_2SO_4 + 3 H_2O$From the stoichiometry of the balanced equation,$2 	ext{ moles of } KMnO_4$ react with $5 	ext{ moles of } Na_2SO_3$.Therefore,$1 	ext{ mole of } KMnO_4$ will react with $\frac{5}{2} = 2.5 	ext{ moles of } Na_2SO_3$.

The number of moles of sodium sulphite $(Na_2SO_3)$ needed to react with one mole of $KMnO_4$ in acidic solution is:

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