The number of geometrical isomers of the comp | vedclass

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Question

(A) The given complex is $[Co(NO_2)_2(NH_3)_2]$. Assuming a square planar geometry (as it is a $4$-coordinate complex),it follows the form $[MA_2B_2]$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) The given complex is $[Co(NO_2)_2(NH_3)_2]$. Assuming a square planar geometry (as it is a $4$-coordinate complex),it follows the form $[MA_2B_2]$.For a square planar complex of the type $[MA_2B_2]$,there are $2$ possible geometrical isomers: $cis$ and $trans$.In the $cis$ isomer,the identical ligands are adjacent to each other.In the $trans$ isomer,the identical ligands are opposite to each other.Therefore,the total number of geometrical isomers is $2$.

The number of geometrical isomers of the complex $[Co(NO_2)_2(NH_3)_2]$ is

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