The number of elements in the 5^{th} period o | vedclass

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(C) The $5^{th}$ period starts with atomic number $37$ $(Rb)$ and ends with atomic number $54$ $(Xe)$.These elements involve the filling of $5s$,$4d$,

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(C) The $5^{th}$ period starts with atomic number $37$ $(Rb)$ and ends with atomic number $54$ $(Xe)$.These elements involve the filling of $5s$,$4d$,and $5p$ orbitals.The number of elements in a period is determined by the number of electrons that can be accommodated in these orbitals.Total number of elements = (number of electrons in $5s$) + (number of electrons in $4d$) + (number of electrons in $5p$) = $2 + 10 + 6 = 18$ elements.

List-$I$	List-$II$
$(1)$ $Unnilbium$	$(A)$ $Db$
$(2)$ $Unnilennium$	$(B)$ $Lr$
$(3)$ $Unnilpentium$	$(C)$ $Mt$
$(4)$ $Unniltrium$	$(D)$ $Bh$
	$(E)$ $No$
	$(F)$ $Rg$

The number of elements in the $5^{th}$ period of the periodic table are

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Match the elements in List-$I$ with their symbols in List-$II$.

List-$I$ List-$II$

$(1)$ $Unnilbium$ $(A)$ $Db$

$(2)$ $Unnilennium$ $(B)$ $Lr$

$(3)$ $Unnilpentium$ $(C)$ $Mt$

$(4)$ $Unniltrium$ $(D)$ $Bh$

$(E)$ $No$

$(F)$ $Rg$

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