Easy
The number of electrons that can be accommodated in $d_{z^2}$ orbital is
- A$10$
- B$1$
- C$4$
- D$2$
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Similar Questions
Consider the ground state of $Cr$ $(Z = 24)$. The numbers of electrons with the azimuthal quantum numbers,$l = 1$ and $l = 2$ are,respectively:
MediumAIEEE 2004
View SolutionMatch List-$I$ with List-$II$.
List-$I$ (Quantum Number) List-$II$ (Information provided) $A$. $m_l$ $I$. Shape of orbital $B$. $m_s$ $II$. Size of orbital $C$. $l$ $III$. Orientation of orbital $D$. $n$ $IV$. Orientation of spin of electron
Choose the correct answer from the options given below:
| List-$I$ (Quantum Number) | List-$II$ (Information provided) |
|---|---|
| $A$. $m_l$ | $I$. Shape of orbital |
| $B$. $m_s$ | $II$. Size of orbital |
| $C$. $l$ | $III$. Orientation of orbital |
| $D$. $n$ | $IV$. Orientation of spin of electron |
Choose the correct answer from the options given below:
MediumNEET 2024
View SolutionValues of the four quantum numbers for the last electron in the atom are $n = 4, l = 1, m = +1$ and $s = -1/2$. Atomic number of the atom will be
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View SolutionWhich of the following orbitals does not have any directional properties?
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View SolutionThe magnetic quantum number specifies
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