(B) The electronic configuration of nitrogen $(N)$ is $1s^2 2s^2 2p^3$. To complete its octet,each nitrogen atom requires $3$ more electrons. Therefor

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(B) The electronic configuration of nitrogen $(N)$ is $1s^2 2s^2 2p^3$. To complete its octet,each nitrogen atom requires $3$ more electrons. Therefore,in the $N_2$ molecule,each nitrogen atom shares $3$ electrons with the other to form a triple covalent bond $(N \equiv N)$.