The number of electrons passing per second through a cross-section of copper wire carrying $10^{-6} \ A$ of current is found to be:

  • A
    $1.6 \times 10^{-19}$
  • B
    $6 \times 10^{-35}$
  • C
    $6 \times 10^{-16}$
  • D
    $6 \times 10^{12}$

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