The number of electrons in 1.6 , C charge wil | vedclass

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(A) According to the quantization of charge,the total charge $q$ is given by $q = ne$,where $n$ is the number of electrons and $e$ is the elementary c

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$10^{19}$

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(A) According to the quantization of charge,the total charge $q$ is given by $q = ne$,where $n$ is the number of electrons and $e$ is the elementary charge.Given: $q = 1.6 \, C$ and $e = 1.6 	imes 10^{-19} \, C$.To find the number of electrons $n$,we use the formula $n = \frac{q}{e}$.Substituting the values: $n = \frac{1.6}{1.6 	imes 10^{-19}} = \frac{1}{10^{-19}} = 10^{19}$.Therefore,the number of electrons is $10^{19}$.

The number of electrons in $1.6 \, C$ charge will be

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