The number of different substitution products | vedclass

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(B) The reaction of ethane $(CH_3-CH_3)$ with bromine $(Br_2)$ leads to the substitution of hydrogen atoms by bromine atoms. The possible substitution

Vedclass · Accepted Answer

$8$

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(B) The reaction of ethane $(CH_3-CH_3)$ with bromine $(Br_2)$ leads to the substitution of hydrogen atoms by bromine atoms. The possible substitution products are:$1$. $CH_3-CH_2Br$ (Bromoethane)$2$. $CH_3-CHBr_2$ ($1$,$1$-Dibromoethane)$3$. $CH_2Br-CH_2Br$ ($1$,$2$-Dibromoethane)$4$. $CH_3-CBr_3$ ($1$,$1$,$1$-Tribromoethane)$5$. $CH_2Br-CHBr_2$ ($1$,$1$,$2$-Tribromoethane)$6$. $CHBr_2-CHBr_2$ ($1$,$1$,$2$,$2$-Tetrabromoethane)$7$. $CHBr_2-CBr_3$ (Pentabromoethane)$8$. $CBr_3-CBr_3$ (Hexabromoethane)There are a total of $8$ possible substitution products.

The number of different substitution products possible when bromine and ethane are allowed to react is:

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