The number of coulombs required to reduce 12. | vedclass

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(D) The chemical equation for the reduction of nitrobenzene to aniline is:$C_6H_5NO_2 + 6H^+ + 6e^- 	o C_6H_5NH_2 + 2H_2O$The molar mass of nitrobenz

Vedclass · Accepted Answer

$57900$

Vedclass · Answer

(D) The chemical equation for the reduction of nitrobenzene to aniline is:$C_6H_5NO_2 + 6H^+ + 6e^- 	o C_6H_5NH_2 + 2H_2O$The molar mass of nitrobenzene $(C_6H_5NO_2)$ is $123 \ g/mol$.From the balanced equation,$1 \ mol$ of nitrobenzene requires $6 \ mol$ of electrons.Charge required for $1 \ mol$ of nitrobenzene $= 6 	imes 96500 \ C = 579000 \ C$.Number of moles of nitrobenzene in $12.3 \ g = \frac{12.3 \ g}{123 \ g/mol} = 0.1 \ mol$.Therefore,the charge required for $0.1 \ mol$ of nitrobenzene $= 0.1 	imes 579000 \ C = 57900 \ C$.

The number of coulombs required to reduce $12.3 \ g$ of nitrobenzene to aniline is:

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