The number of asymmetric carbon atoms in the | vedclass

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(C) The chemical formula for glucose is $CH_2OH-(CHOH)_4-CHO$.In the open-chain structure of glucose,there are $6$ carbon atoms in total.The carbon at

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$4$

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(C) The chemical formula for glucose is $CH_2OH-(CHOH)_4-CHO$.In the open-chain structure of glucose,there are $6$ carbon atoms in total.The carbon atom at position $1$ is part of the aldehyde group $(-CHO)$,and the carbon atom at position $6$ is part of the primary alcohol group $(-CH_2OH)$.The carbon atoms at positions $2, 3, 4,$ and $5$ are each bonded to four different groups ($-H, -OH, -CHO/CH_2OH,$ and the rest of the carbon chain).Therefore,these $4$ carbon atoms are asymmetric (chiral) centers.Thus,the total number of asymmetric carbon atoms in a glucose molecule is $4$.

The number of asymmetric carbon atoms in the glucose molecule is:

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