The number of P-OH bonds and the oxidation st | vedclass

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(D) The structure of pyrophosphoric acid $(H_4P_2O_7)$ consists of two $PO_4$ tetrahedra linked by an oxygen atom $(P-O-P)$.Each phosphorus atom is bo

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four and five

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(D) The structure of pyrophosphoric acid $(H_4P_2O_7)$ consists of two $PO_4$ tetrahedra linked by an oxygen atom $(P-O-P)$.Each phosphorus atom is bonded to two $OH$ groups,one terminal oxygen atom via a double bond,and one bridging oxygen atom.Therefore,the total number of $P-OH$ bonds is $4$ (two per phosphorus atom).To calculate the oxidation state of $P$ in $H_4P_2O_7$:Let the oxidation state of $P$ be $x$.$4(+1) + 2(x) + 7(-2) = 0$$4 + 2x - 14 = 0$$2x = 10$$x = +5$Thus,the number of $P-OH$ bonds is $4$ and the oxidation state of phosphorus is $+5$.

The number of $P-OH$ bonds and the oxidation state of the phosphorus atom in pyrophosphoric acid $(H_4P_2O_7)$ respectively are

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