The nature of a graph drawn for a freely fall | vedclass

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(B) For a freely falling body,the equation of motion for velocity is given by $v = u + gt$. Since the initial speed $u = 0$,the equation becomes $v =

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a straight line passing through the origin.

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(B) For a freely falling body,the equation of motion for velocity is given by $v = u + gt$. Since the initial speed $u = 0$,the equation becomes $v = gt$. Here,$g$ is the acceleration due to gravity,which is a constant ($g \approx 9.8 \ m/s^2$ or $10 \ m/s^2$). This equation $v = gt$ is of the form $y = mx$,where $y$ represents speed,$x$ represents time,and $m = g$ is the slope. Since there is no constant term (intercept),the graph is a straight line passing through the origin $(0, 0)$. Therefore,the correct option is $B$.

The nature of a graph drawn for a freely falling body with time on the $x$-axis and speed on the $y$-axis is (Assuming initial speed to be zero.)

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