The most suitable reagent for the given conve | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given conversion involves the reduction of a carboxylic acid group $(-COOH)$ to a primary alcohol $(-CH_2OH)$ while leaving the ketone $(-COCH

Vedclass · Accepted Answer

$B_2H_6$

Vedclass · Answer

(D) The given conversion involves the reduction of a carboxylic acid group $(-COOH)$ to a primary alcohol $(-CH_2OH)$ while leaving the ketone $(-COCH_3)$,amide $(-CONH_2)$,and nitrile $(-CN)$ groups unaffected.$B_2H_6$ (diborane) is a selective electrophilic reducing agent that reduces carboxylic acids to primary alcohols much faster than it reduces other functional groups like ketones,amides,or nitriles under controlled conditions.$LiAlH_4$ is a strong reducing agent that would reduce all these groups ($-COOH$,$-COCH_3$,$-CONH_2$,$-CN$).$NaBH_4$ is a milder reducing agent but is generally not effective for reducing carboxylic acids directly.$H_2/Pd$ would reduce the ketone and potentially the nitrile group.Therefore,$B_2H_6$ is the most suitable reagent.

The most suitable reagent for the given conversion is

Similar Questions

Arrange the following compounds in order of their reactivity toward $LiAlH_4$:
$(i)$ Cyclopentanone
(ii) $N$-Methylpyrrolidin$-2-$one
(iii) $\gamma$-Butyrolactone

$RCOOH + NaHCO_3 \to RCOONa + H_2O + CO_2$. In this reaction,the $CO_2$ evolved comes from:

What is the correct order of acidity of compounds $(I)$,$(II)$,and $(III)$?
$(I)$ $4$-Nitrobenzoic acid
$(II)$ $4$-Methoxybenzoic acid
$(III)$ Benzoic acid

The unknown product $(A)$ is:

When $CH_3COOH$ reacts with $CH_3MgX$,what is the primary product formed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module