The most basic hydroxide among the following | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The basicity of lanthanide hydroxides decreases as the ionic radius decreases with an increase in atomic number (lanthanide contraction).Therefore

Vedclass · Accepted Answer

$Ce(OH)_3$

Vedclass · Answer

(B) The basicity of lanthanide hydroxides decreases as the ionic radius decreases with an increase in atomic number (lanthanide contraction).Therefore,the basicity follows the order: $La(OH)_3 > Ce(OH)_3 > ... > Lu(OH)_3$.Comparing $Ce(OH)_3$ and $Ce(OH)_4$,the hydroxide with the lower oxidation state of the metal $(Ce^{3+})$ is more basic than the one with the higher oxidation state $(Ce^{4+})$ because the higher charge density of $Ce^{4+}$ increases the covalent character of the $Ce-OH$ bond.Thus,$Ce(OH)_3$ is the most basic among the given options.

The most basic hydroxide among the following is

Similar Questions

Which of the following statements regarding copper salts is not true?

Which of the following statements is true regarding the structure of $Cr_2O_7^{2-}$?

$NaCl$ reacts with conc. $H_2SO_4$ and $K_2Cr_2O_7$ to give reddish fumes $(B)$,which react with $NaOH$ to give yellow solution $(C)$. $(B)$ and $(C)$ respectively are:

$A$ blue borax bead is obtained with:

What happens when potassium chromate reacts with dilute nitric acid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module