The monomers of nylon$-6, 6$ $(X)$ and terylene $(Y)$ are

  • A
    Nylon$-6, 6$ $(X)$: $H_2N-(CH_2)_5-CH_3$,$HOOC-(CH_2)_4-CH_3$; Terylene $(Y)$: $HO-CH_2-CH_3$,$HO-C_6H_4-COOH$
  • B
    Nylon$-6, 6$ $(X)$: $H_2N-(CH_2)_4-NH_2$,$HOOC-(CH_2)_4-COOH$; Terylene $(Y)$: $HO-CH_2-CH_2-OH$,$C_6H_4(COOH)_2$ (ortho)
  • C
    Nylon$-6, 6$ $(X)$: $H_2N-CH_2-COOH$,$H_2N-(CH_2)_5-COOH$; Terylene $(Y)$: $HO-CH_2-CH_2-OH$,$HO-C_6H_4-COOH$
  • D
    Nylon$-6, 6$ $(X)$: $H_2N-(CH_2)_6-NH_2$,$HOOC-(CH_2)_4-COOH$; Terylene $(Y)$: $HO-CH_2-CH_2-OH$,$HOOC-C_6H_4-COOH$ (terephthalic acid)

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Match $List-I$ with $List-II$.
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Choose the correct answer from the options given below.

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