The momentum of a photon of energy 1 , MeV in | vedclass

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Question

(A) The energy of the photon is given as $E = 1 \, MeV = 1 	imes 10^6 \, eV$.Converting energy into Joules: $E = 10^6 	imes 1.6 	imes 10^{-19} \, J

Vedclass · Accepted Answer

$5 	imes 10^{-22}$

Vedclass · Answer

(A) The energy of the photon is given as $E = 1 \, MeV = 1 	imes 10^6 \, eV$.Converting energy into Joules: $E = 10^6 	imes 1.6 	imes 10^{-19} \, J = 1.6 	imes 10^{-13} \, J$.The momentum $p$ of a photon is related to its energy $E$ by the formula $p = E/c$,where $c$ is the speed of light $(c \approx 3 	imes 10^8 \, m/s)$.Substituting the values: $p = \frac{1.6 	imes 10^{-13} \, J}{3 	imes 10^8 \, m/s}$.$p \approx 0.533 	imes 10^{-21} \, kg \, m/s$.$p \approx 5.33 	imes 10^{-22} \, kg \, m/s$.Rounding to the nearest given option,the correct value is $5 	imes 10^{-22} \, kg \, m/s$.

The momentum of a photon of energy $1 \, MeV$ in $kg \, m/s$ will be:

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