The molecule having the smallest bond angle i | vedclass

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(C) In the series $NCl_3, PCl_3, AsCl_3$,and $SbCl_3$,all central atoms belong to Group $15$ and possess one lone pair of electrons.As we move down th

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$SbCl_3$

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(C) In the series $NCl_3, PCl_3, AsCl_3$,and $SbCl_3$,all central atoms belong to Group $15$ and possess one lone pair of electrons.As we move down the group from $N$ to $Sb$,the electronegativity of the central atom decreases,and its atomic size increases.According to $VSEPR$ theory,as the size of the central atom increases,the bond pairs are located further away from the central atom.This leads to a reduction in the repulsion between the bond pairs,which results in a decrease in the bond angle.Therefore,$SbCl_3$ has the smallest bond angle among the given molecules.

List-$I$	List-$II$
$A. ICl$	$i. \text{Linear}$

$B. ICl_3$	$ii. \text{T-Shape}$
$C. ClF_5$	$iii. \text{Square pyramidal}$
$D. IF_7$	$iv. \text{Pentagonal bipyramidal}$

The molecule having the smallest bond angle is:

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Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A. ICl$ $i. \text{Linear}$
$B. ICl_3$ $ii. \text{T-Shape}$
$C. ClF_5$ $iii. \text{Square pyramidal}$
$D. IF_7$ $iv. \text{Pentagonal bipyramidal}$

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