The molecule having one unpaired electron is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Molecular Orbital Theory $(MOT)$,the electronic configurations are as follows:$A].$ For $NO$ ($15$ electrons): $\sigma 1s^2, \sigma^*

Vedclass · Accepted Answer

$NO$

Vedclass · Answer

(A) According to Molecular Orbital Theory $(MOT)$,the electronic configurations are as follows:$A].$ For $NO$ ($15$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^2, \pi^* 2p_x^1$. It has $1$ unpaired electron.$B].$ For $CO$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^2$. All electrons are paired.$C].$ For $CN^{-}$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^2$. All electrons are paired.$D].$ For $O_2$ ($16$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^2, \pi^* 2p_x^1, \pi^* 2p_y^1$. It has $2$ unpaired electrons.Thus,$NO$ is the correct molecule.

Similar Questions

In which of the following circuits is the current maximum just after the switch $S$ is closed?

What are the oxidation states of iron and chromium in chromite ore,respectively?

Two radioactive materials $X_1$ and $X_2$ have decay constants $10 \lambda$ and $\lambda$ respectively. If initially they have the same number of nuclei,then the ratio of the number of nuclei of $X_1$ to that of $X_2$ will be $1 / e$ after a time:

If $5 \cos x + 12 \cos y = 13$,then the maximum value of $5 \sin x + 12 \sin y$ is:

$SO_{2}$ is a strong reducing agent; however,it can also act as an oxidising agent. Which of the following shows its oxidising nature?

Vedclass Test Series

Exam Paper Generator

Online Exam Module