The molecular formula of a crystal is AB_2O_4 | vedclass

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(A) In a $ccp$ lattice,if the number of oxygen atoms is $4$,then:Number of octahedral voids $= 4$Number of tetrahedral voids $= 8$Given the formula $A

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$12.5 \%, 50 \%$

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(A) In a $ccp$ lattice,if the number of oxygen atoms is $4$,then:Number of octahedral voids $= 4$Number of tetrahedral voids $= 8$Given the formula $AB_2O_4$,there are $1$ atom of $A$,$2$ atoms of $B$,and $4$ atoms of $O$.For atom $A$ in tetrahedral voids: $x \% 	ext{ of } 8 = 1 \implies x = (1/8) 	imes 100 = 12.5 \%$.For atom $B$ in octahedral voids: $y \% 	ext{ of } 4 = 2 \implies y = (2/4) 	imes 100 = 50 \%$.Thus,$x = 12.5 \%$ and $y = 50 \%$.

The molecular formula of a crystal is $AB_2O_4$. Oxygen atoms form $ccp$ lattice. Atoms of $A$ occupy $x \%$ of tetrahedral voids and atoms of $B$ occupy $y \%$ of octahedral voids. $x$ and $y$ are respectively:

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