(A) The molarity of the final mixture is calculated using the formula:$M_{mix} = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}$Given:$M_{1} = 0.5 \, M

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(A) The molarity of the final mixture is calculated using the formula:$M_{mix} = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}$Given:$M_{1} = 0.5 \, M$,$V_{1} = 750 \, mL$$M_{2} = 2 \, M$,$V_{2} = 250 \, mL$Total volume $V = 750 \, mL + 250 \, mL = 1000 \, mL$Substituting the values:$M_{mix} = \frac{(0.5 \times 750) + (2 \times 250)}{1000}$$M_{mix} = \frac{375 + 500}{1000} = \frac{875}{1000} = 0.875 \, M$

Class 12 Chemistry Solutions Method of expressing concentration of solution

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The molarity of a solution obtained by mixing $750 \, mL$ of $0.5 \, M \, HCl$ with $250 \, mL$ of $2 \, M \, HCl$ will be $......... \, M$.

JEE MAIN 2013 All JEE MAIN

A
$0.875$
B
$1.00$
C
$1.75$
D
$0.97$

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The molarity of a solution obtained by mixing $750 \, mL$ of $0.5 \, M \, HCl$ with $250 \, mL$ of $2 \, M \, HCl$ will be $......... \, M$.

Similar Questions

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