The molar conductivity of a conductivity cell | vedclass

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(A) The formula for molar conductivity is $\Lambda_{m} = \kappa 	imes \frac{1000}{M}$,where $M$ is the molarity of the solution.Since the conductivit

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$\Lambda_{m2} = 2 \Lambda_{m1}$

Vedclass · Answer

(A) The formula for molar conductivity is $\Lambda_{m} = \kappa 	imes \frac{1000}{M}$,where $M$ is the molarity of the solution.Since the conductivities $\kappa$ are the same,$\Lambda_{m} \propto \frac{1}{M}$.Calculate the molarity for both solutions:$M_1 = \frac{n_1}{V_1} = \frac{10 \ mol}{20 \ mL} = 0.5 \ mol/mL$.$M_2 = \frac{n_2}{V_2} = \frac{20 \ mol}{80 \ mL} = 0.25 \ mol/mL$.Now,find the ratio:$\frac{\Lambda_{m2}}{\Lambda_{m1}} = \frac{M_1}{M_2} = \frac{0.5}{0.25} = 2$.Therefore,$\Lambda_{m2} = 2 \Lambda_{m1}$.

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