The molar conductivity of $0.025 \ M$ methanoic acid is $46.1 \ S \ cm^2 \ mol^{-1}$. Calculate its degree of dissociation. Given: $\lambda^0(H^{+}) = 349.6 \ S \ cm^2 \ mol^{-1}$ and $\lambda^0(HCOO^{-}) = 54.6 \ S \ cm^2 \ mol^{-1}$.

  • A
    $0.414$
  • B
    $0.114$
  • C
    $8.767$
  • D
    $7.867$

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