The molar conductivities Lambda_{NaOH}^o and | vedclass

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(B) According to Kohlrausch's law of independent migration of ions,the molar conductivity of a weak electrolyte like acetic acid $(CH_3COOH)$ at infin

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$\Lambda_{NaCl}^o$

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(B) According to Kohlrausch's law of independent migration of ions,the molar conductivity of a weak electrolyte like acetic acid $(CH_3COOH)$ at infinite dilution can be calculated using the molar conductivities of strong electrolytes.The expression is:$\Lambda_{CH_3COOH}^o = \Lambda_{CH_3COONa}^o + \Lambda_{HCl}^o - \Lambda_{NaCl}^o$Given that we have $\Lambda_{HCl}^o$,we need $\Lambda_{CH_3COONa}^o$ and $\Lambda_{NaCl}^o$ to complete the calculation. However,if the question implies we are starting from a set of values,the missing component to relate these to acetic acid is $\Lambda_{CH_3COONa}^o$ and $\Lambda_{NaCl}^o$. Based on the provided options,$\Lambda_{NaCl}^o$ is the standard additional value required to cancel out the ions not present in the target electrolyte.

The molar conductivities $\Lambda_{NaOH}^o$ and $\Lambda_{HCl}^o$ at infinite dilution in water at $25 ^\circ C$ are $91.0$ and $426.2 \ S \ cm^2/mol$ respectively. To calculate $\Lambda_{CH_3COOH}^o$,the additional value required is:

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