The metal ion (in gaseous state) with the low | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The spin-only magnetic moment $(\mu)$ is given by the formula $\mu = \sqrt{n(n+2)} \ BM$, where $n$ is the number of unpaired electrons.To find th

Vedclass · Accepted Answer

$Ni^{2+}$

Vedclass · Answer

(B) The spin-only magnetic moment $(\mu)$ is given by the formula $\mu = \sqrt{n(n+2)} \ BM$, where $n$ is the number of unpaired electrons.To find the lowest magnetic moment, we need to identify the ion with the minimum number of unpaired electrons $(n)$.$1$. $V^{2+}$ $(Z=23)$: Electronic configuration is $[Ar] 3d^3$. Number of unpaired electrons $(n)$ = $3$.$2$. $Ni^{2+}$ $(Z=28)$: Electronic configuration is $[Ar] 3d^8$. Number of unpaired electrons $(n)$ = $2$.$3$. $Cr^{2+}$ $(Z=24)$: Electronic configuration is $[Ar] 3d^4$. Number of unpaired electrons $(n)$ = $4$.$4$. $Fe^{2+}$ $(Z=26)$: Electronic configuration is $[Ar] 3d^6$. Number of unpaired electrons $(n)$ = $4$.Since $Ni^{2+}$ has the lowest number of unpaired electrons $(n=2)$, it has the lowest spin-only magnetic moment value.

The metal ion (in gaseous state) with the lowest spin-only magnetic moment value is .... .

Similar Questions

What should be the difference in atomic radii between two metal elements to form an alloy?

Which of the following substances will have the highest magnetic moment for its transition metal ion?

Which atom or ion has a pseudo inert gas configuration?

The transition metal which shows oxidation states from $+2$ to $+7$ belongs to group:

The catalytic activity of transition metals and their compounds is due to their

Vedclass Test Series

Exam Paper Generator

Online Exam Module